On Jun 24, 9:54 am, Ronan Lamy <[email protected]> wrote:
> > For example, complex infinity is a correct value for 1/sin(x) at x = 0
> > because the limit could be -infinity or +infinity depending on the
> > direction of the limit along the real line, or it could be an infinity
> > with any complex phase when approached through the complex plane.
>
> > On the other hand log(0) = -infinity because log(x) tends to -infinity
> > no matter the direction of approach.
>
> > Fredrik
>
> No, log(0) has to be ComplexInfinity.

Wolfram says that log(0) = -infinity.

> Otherwise, limit(1/exp(log(-x), x,
> 0, "+") = +infinity !

Check this link:
http://www53.wolframalpha.com/input/?i=+limit+(1%2Fexp(log(-x))+as+x-%3E0%2B

~Luke
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