On Sun, Jan 10, 2010 at 6:37 AM, Kasun Samarasinghe
<[email protected]> wrote:
> Thank you for the reply. Actually I was solving a problem where i need to
> integrate from
> minus infinity to plus infinity. Can I do that in the way you mentioned?

Yes:

In [2]: integrate(1/(1+x**2), (x, -oo, oo))
Out[2]: π

but if the integral is too complicated, you may need to enhance our
definite integral algorithm.

Ondrej
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