Le jeudi 22 avril 2010 à 17:15 -0700, pallab a écrit :
> > > At=x*y
> > > x=4
> > > y=3
> > > N(At)
> >
> > > gives me x*y. Is it ok, should it be the intended behavior?
>
> Sorry that the question was not clear. is it the intended behaviour in
> N()?. It is ok if At prints x*y, that is understandable.
N(expression) converts all the numbers in the expression to floating
point. Here, there are no numbers, so N(At) returns At, which is equal
to Symbol('x')*Symbol('y').
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