>
> Now the question is if I then set diff_flg=True is there a way to recalculate
> z so that z = 2*x_1+x_1**2+x_2**2 is returned.
>
That's what happens for me:
In [58]: exec"""
from sympy import *
x_1 = Symbol('x_1')
x_2 = Symbol('x_2')
df = Function('df')
diff_flg = True
def df_1(F):
global x_1,diff_flg
if diff_flg:
return(diff(F,x_1))
else:
return(df(F))
if __name__ == '__main__':
x = Symbol('x')
df = Function('df')
print df
y = x_1**2+x_2**2
print x,x_1,x_2,y
z = y + df_1(y)
print z
"""
df
x x_1 x_2 x_1**2 + x_2**2
2*x_1 + x_1**2 + x_2**2
Are you saying you want it to happen automatically, without recalculating z?
In that case, you will need to make z itself a function. See
http://docs.sympy.org/gotchas.html#variables-assignment-does-not-create-a-relation-between-expressions.
Aaron Meurer
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