Hi, On 23 October 2010 10:22, Chenjie Gu <[email protected]> wrote:
> Thanks a lot for the reply. I'll read the match algorithm later. > > But for the script you gave, it seems that in my version of sympy, there's > no function called "as_Add()". > I am using sympy 0.6.7. Are you using a higher version of sympy? > If there is no as_Add() (possibly it was added after last release), then use: In [1]: make_list(1 + x, Add) Out[1]: [1, x] > > Chenjie > > > On Sat, Oct 23, 2010 at 1:06 AM, smichr <[email protected]> wrote: > >> ...and if you only want terms that acutally have x then also use the >> method .has(): >> >> >> h[1] >>> [a for a in (1+x).as_Add() if a.is_polynomial(x)] >> [1, x] >> h[2] >>> [a for a in (1+x).as_Add() if a.has(x) and >> a.is_polynomial(x)] >> [x] >> h[3] >>> >> >> >> >> >> >> >> /c >> >> -- >> You received this message because you are subscribed to the Google Groups >> "sympy" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected] <sympy%[email protected]> >> . >> For more options, visit this group at >> http://groups.google.com/group/sympy?hl=en. >> >> > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected] <sympy%[email protected]>. > For more options, visit this group at > http://groups.google.com/group/sympy?hl=en. > Mateusz -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
