On Feb 24, 2011, at 4:33 AM, Alexander Eberspächer wrote: > Hello, > > On Thu, 24 Feb 2011 09:58:59 +0300 > "Alexey U. Gudchenko" <[email protected]> wrote: > >> And I have some little question about Laurent. >> >> exp(1/x).series(x, oo) = 1 + 1/x + 1/(2*x**2) ... >> >> Is it Laurent or power series? > > In my use of maths language, this is a Laurent series as negative > powers of x contribute. Power series (or, in this case, Taylor series) > contain only exponents in [0; oo). So I would call this expansion a > Laurent series about the point x=oo. > > Quickly browsing through the Mathematica 8 documentation, it seems that > Mathematica does not offer more much functionality than SymPy does (or > will do with that Series branch). The documentation also is fuzzy about > terminology. It describes that Series[] gives a series that may be a > (truncated ) Taylor series or another, more general type of series with > generalized powers (such as fractional powers). I haven't found a > command to explicitly generate Laurent series. > > Cheers > > Alex
I think Mathematica can do more than SymPy, because for example, if you type "series of sin(x)" into Wolfram|Alpha (http://www.wolframalpha.com/input/?i=series%20of%20sin(x)), you get both x-x^3/6+x^5/120-x^7/5040+x^9/362880+O(x^10) and sin(x) = sum_(k=0)^infinity((-1)^k x^(1+2 k))/((1+2 k)!). Aaron Meurer -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
