exp(O(x)).series() fails with the following ValueError: Could not
calculate 6 terms for exp(O(x)). On the other hand exp(O(x)).series(n=1)
succeeds and give the expected result. Is this a feature preventing me
to ask too precise Taylor expansion ? If yes, is there a way to ask the
series to return what I expected ? I'd like an expansion as far as
possible, with a maximum at O(x**n), of course.
Below, a cut-n-pasted version of my trial, in the git master branch.
Fred
In [6]: exp(O(x)).series()
---------------------------------------------------------------------------
ValueError Traceback (most recent call
last)
/home/fred/git/sympy/<ipython console> in <module>()
/home/fred/git/sympy/sympy/core/expr.pyc in series(self, x, x0, n, dir)
1257 else:
1258 raise ValueError('Could not calculate %s
terms for %s'
-> 1259 % (str(n), self))
1260 o = s1.getO()
1261 s1 = s1.removeO()
ValueError: Could not calculate 6 terms for exp(O(x))
In [7]: exp(O(x)).series(n=1)
Out[7]: 1 + O(x)
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