On Apr 29, 2:17 pm, Ronan Lamy <[email protected]> wrote:
> I would argue that the correct results are limit(x - oo, x, oo) == -oo
> and limit(oo - x, x, oo) == oo.
>
> The expression whose limit is taken belongs to the extended real line,
> so we need to consider the topology of the extended real line. Unless
> otherwise specified, limits are always evaluated for values of the
> variable close to, but different from, the "destination". In this case,
> this means arbitrarily large, but finite, reals. For any real x, x - oo
> = -oo, so the function Lambda(x, x - oo) is constant over the reals, but
> discontinuous, undefined actually, at x = +oo. However, the latter
> doesn't matter for the limit, and the result is the constant value, -oo.
> All this is completely parallel to limit(abs(x)/x, x, 0, '+'), for
> instance.

Take f(x,y)=x-y. By your account lim(lim(f(x,y),y,oo),x,oo) == -oo but
lim(lim(f(x,y),x,oo),y,oo) == oo. This can't be right.

--
Julien

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