Thanks for the quick reply Aaron.  I will get the latest git version
and run with it.  BTW, I was running the sample on 0.6.7.

Thanks again,
Matt

On Thu, May 26, 2011 at 08:28:51PM -0600, Aaron S. Meurer wrote:
> If I try this with mpmath 0.16 (the version we currently have in sympy in the 
> latest git master), I get:
> 
> In [22]: print 'subs:  ', mpmath.findroot(lambda xi: p.subs(x, xi), 1.0)
> subs:  
> ---------------------------------------------------------------------------
> ValueError                                Traceback (most recent call last)
> 
> /Users/aaronmeurer/Documents/python/sympy/sympy/<ipython console> in 
> <module>()
> 
> /Users/aaronmeurer/Documents/python/sympy/sympy/sympy/mpmath/calculus/optimization.pyc
>  in findroot(ctx, f, x0, solver, tol, verbose, verify, **kwargs)
>     968                              '(%g > %g)\n'
>     969                              'Try another starting point or tweak 
> arguments.'
> --> 970                              % (norm(f(*xl))**2, tol))
>     971         return x
>     972     finally:
> 
> ValueError: Could not find root within given tolerance. (6.67917e-33 > 
> 1.71057e-49)
> Try another starting point or tweak arguments.
> 
> Another option for Poly is eval.  I get this:
> 
> In [37]: print 'eval:  ', mpmath.findroot(lambda xi: p.eval(x, xi), 1.0)
> eval:   0.774596669241483377035853079956479922166584341
> 
> In [38]: print 'exact: ', mpmath.sqrt(mpmath.mpf('3.0')/mpmath.mpf('5.0'))
> exact:  0.774596669241483377035853079956479922166584341
> 
> In [39]: print 'lambda:', mpmath.findroot(lambda x: 5.0*x**3/2.0 - 3.0*x/2.0, 
> 1.0)
> lambda: 0.774596669241483377035853079956479922166584341
> 
> So I'd say there is some kind of bug with subs.
> 
> Aaron Meurer
> 
> On May 26, 2011, at 8:21 PM, Matthew Emmett wrote:
> 
> > Hi everyone,
> > 
> > I am having trouble combining mpmath's findroot function with sympy.
> > Here is a short example of what I am trying to accomplish:
> > 
> > import sympy
> > import mpmath
> > 
> > mpmath.mp.dps = 45
> > 
> > x = sympy.var('x')
> > p = (5.0/2.0*x**3 - 3.0/2.0*x).as_poly()
> > 
> > print 'subs:  ', mpmath.findroot(lambda xi: p.subs(x, xi), 1.0)
> > print 'lambda:', mpmath.findroot(lambda x: 5.0*x**3/2.0 - 3.0*x/2.0,
> > 1.0)
> > print 'exact: ', mpmath.sqrt(mpmath.mpf('3.0')/mpmath.mpf('5.0'))
> > 
> > 
> > The output is:
> > 
> > subs:   0.77459666924148342341315597798728447146706553
> > lambda: 0.774596669241483377035853079956479922166584341
> > exact:  0.774596669241483377035853079956479922166584341
> > 
> > 
> > That is, when using mpmath.findroot, substituting into a SymPy
> > polynomial does not produce the same result as using a lambda form
> > with a handwritten version of the polynomial.  Is there a way to the
> > SymPy subs method to work as expected?
> > 
> > Thanks,
> > Matt
> > 
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