On Wed, Jun 15, 2011 at 6:06 PM, Aaron Meurer <[email protected]> wrote:

> The short answer is that the proper way to call it with sort_key() is
> sorted([x, a, b], key=lambda i: i.sort_key()).  default_sort_key() is
> just a shortcut to this lambda expression.  You shouldn't use
> sort_key() unless you want use a nonstandard order (which is broken
> right now anyway).
>
>
But notice that x comes before a and b ... I was wondering if this is
intentional and which makes most sense.

>>    >>> sorted([x, a, b], key=default_sort_key)
> >>    [a, b, x]
> >>    >>> sorted([x, a, b], key=Basic.sort_key)
> >>    [x, a, b]
>

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