>>> help(Line.perpendicular_segment)
Help on method perpendicular_segment in module sympy.geometry.line:
perpendicular_segment(self, p) unbound sympy.geometry.line.Line
method
Returns a new Segment which connects p to a point on this linear
entity and is also perpendicular to this line. Returns p itself
if p is on this linear entity.
>>> l=Line(Point(1,2), Point(2,3))
>>> l.perpendicular_segment(Point(0,0))
Segment(Point(Rational(-1, 2), Half(1, 2)), Point(Zero, Zero))
>>> p=Point(3,4)
>>> p in l
True
>>> l.perpendicular_segment(p)
Point(Integer(3), Integer(4))
Looks like your point in on the line.
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