If you guys have a couple of topics that we could maybe pull others in with let me know.
-- Andy On Tue, Jul 5, 2011 at 8:47 PM, Mateusz Paprocki <[email protected]> wrote: > Hi, > > On 6 July 2011 03:43, Aaron Meurer <[email protected]> wrote: >> >> Yes, I'll be there too. Mateusz wil be at the conference too, though >> I don't know if he will be there for the sprints. If so, we should do >> a sympy sprint. > > I will be in Austin till Sunday, so I can participate in a SymPy sprint for > sure. > >> >> Aaron Meurer >> >> On Tue, Jul 5, 2011 at 7:21 PM, Andy Ray Terrel <[email protected]> >> wrote: >> > Anyone interested in the SciPy sprints? >> > >> > http://conference.scipy.org/scipy2011/sprints.php >> > >> > I should be around. >> > >> > -- Andy >> > >> > -- >> > You received this message because you are subscribed to the Google >> > Groups "sympy" group. >> > To post to this group, send email to [email protected]. >> > To unsubscribe from this group, send email to >> > [email protected]. >> > For more options, visit this group at >> > http://groups.google.com/group/sympy?hl=en. >> > >> > >> >> -- >> You received this message because you are subscribed to the Google Groups >> "sympy" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/sympy?hl=en. >> > > Mateusz > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/sympy?hl=en. > -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
