On Fri, Sep 16, 2011 at 2:40 AM, Chris Smith <[email protected]> wrote:
> instead of `a%p` write `a % p`. Also, since this will have to be
> computed again later you might as well do both at the same time:
>
> a, r = divmod(a, p)
if not r:
> return 0
> if is_quad_residue(a, p):
> return 1
> else:
> return -1
>
for a, p = 5, 11; divmod(a, p) returns (0, 5) and we will be losing the
value of a if a < p and hence with little modification -
_, r = divmod(a, p)
if not r:
return 0
else:
a = r
if is_quad_residue(a, p):
return 1
else:
return -1
>
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--
-Regards
Hector
Whenever you think you can or you can't, in either way you are right.
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