I get the same thing as you interactively but my tests pass. Since
both solutions are equivalent, just turn this (back?) into a test of
solve(...) in [ans1, ans2].
>>> eq = ((2**exp(y**2/x) + 2)/(x**2 + 15))
>>> ans1= solve(eq, y)
>>> [eq.subs(y,a).subs(x,.1).n(2) for a in ans1]
[.0e-112 + 2.5e-117*I, .0e-112 + 2.5e-117*I]
>>> ans2 = [-sqrt(x)*sqrt(log((log(2) + I*pi)/log(2))), sqrt(x)*sqrt(log
((log(2) + I*pi)/log(2)))]
>>> [eq.subs(y,a).subs(x,.1).n(2) for a in ans2]
[.0e-112 + 2.5e-117*I, .0e-112 + 2.5e-117*I]
>>> ans1[0].subs(x,.1).n(2)
-0.42 - 0.16*I
>>> ans2[0].subs(x,.1).n(2)
-0.42 - 0.16*I
>>> ans1[1].subs(x,.1).n(2)
0.42 + 0.16*I
>>> ans2[1].subs(x,.1).n(2)
0.42 + 0.16*I
>>> ans1 == ans2
False
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