Aaron Meurer wrote:
> > Discontinuous functions may pose problems for the moment (none seen for the
> > moment, but this is mostly by chance).
>
> As far as I can tell, this is a nontrivial problem to solve, as many
> very good plotting systems choke on discontinuous functions.  Perhaps
> there can be some kind of symbolic heuristic applied to find
> discontinuities.

IIRC, discontinuities where the funtion approaches infinity (like 1/x
for x -> 0) can also be found numerically using Newton's method (with
phi(x) = x + f(x)/f'(x) for iteration).

Vinzent

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