Thank you very much it indeed works with "mpmath" in lambdify. However my final goal would be to actually use numpy to evaluate that value (as a function of n and d) in another program that has no dependency on sympy nor mpmath.
Do you think there is a way to make sympy refactor the expression so that the naive numpy translation would be more stable, especially for the range of d and n is such that the solution has an imaginary part close to or exactly zero? I will try to further investigate. -- Olivier -- You received this message because you are subscribed to the Google Groups "sympy" group. To view this discussion on the web visit https://groups.google.com/d/msg/sympy/-/yQddw56BoSwJ. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
