How can I represent an unevaluated call to nsolve as a sympy expression? Is Lambda the best (and standard) solution?
The expression I want to represent looks like nsolve(x-tanh(x-h),[x],0). The free symbol is h. It's in the context of plotting phase transition diagrams. -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
