Arg, of course. These symbols are always positive and I forgot to provide
the assumptions kwarg. Sorry I forgot about this.

Thank you for the extra info on posify. I didn't know about this function.

Best,
Casey


On Mon, Feb 20, 2012 at 1:11 AM, prateek papriwal <[email protected]
> wrote:

> also (a**2)**0.5 and (a)**1 are not the same things ..
>
>
> On Mon, Feb 20, 2012 at 2:35 PM, Chris Smith <[email protected]> wrote:
>
>> Since such a transformation is not generally valid, it is disallowed
>> (e.g. if a = -1 then your expression would give 1 while the "simplified"
>> version would give -1). The transformation *is* valid if 'a' is positive,
>> so you can either create a with a positive assumption
>>
>> >>> a = Symbol('a', positive=True)
>> >>> (a**2)**.5
>> a
>>
>> or let posify handle the conversion:
>>
>> >>> eq
>> (a**2)**0.5
>> >>> posify(eq)
>> (_a**1.0, {_a: a})
>> >>> p, r = posify(eq);     p.subs(r)
>> a
>>
>> Chris
>>
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