I think Yes. On Wed, Mar 14, 2012 at 8:57 PM, Gaurav Sathe <[email protected]>wrote:
> Thnx... I was thinking of the same logic which u have said... but then how > do we explain the below series expansion: > > >>> (sin(x)/x**10).series(x,0,10) > 1 1 1 1 1 > ──────── + ── - ──── + ────── - ─────── + O(1) > 362880⋅x 9 7 5 3 > x 6⋅x 120⋅x 5040⋅x > > > Do we say that it is like dividing each term of the sin(x) series by x**10 > ? > > -Gaurav > > > > On Wed, Mar 14, 2012 at 7:44 PM, Sai Nikhil <[email protected]> wrote: > >> parameter 'n' was written to imply last exponent of 'x' in the >> expansion, I guess >> >> but, in second case, exp(x**2) = exp(v), where v = x**2 and so, exp(v) is >> calculated till, v**9 and substituting, v=x**2, we are getting the above >> result. >> >> this is obviously supposed to be an issue, and if Mr.Aaron permits, I'll >> try to submit a suitable patch for this ... >> >> >> *-thanks ,* >> *Sai Nikhil.T <http://www.tsndiffopera.in>* >> >> >> *1* >> >> -- >> You received this message because you are subscribed to the Google Groups >> "sympy" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/sympy?hl=en. >> > > > > -- > Gaurav Sathe > -Student at BITS Pilani - Goa Campus > > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/sympy?hl=en. > -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
