this is working perfectly fine ..thanks a lot On Sat, May 12, 2012 at 5:52 AM, Aaron Meurer <[email protected]> wrote:
> No because we also want something like √2 to work. If you have > something like √2a that will be a syntax error anyway. > > Aaron Meurer > > On May 11, 2012, at 5:43 PM, Chris Smith <[email protected]> wrote: > > >> √([a-zA-Z0-9_]+) -> sqrt\(\1\) > > > > I think that should be √([a-zA-Z_][a-zA-Z0-9_]*) -> sqrt\(\1\) > > > > -- > > You received this message because you are subscribed to the Google > Groups "sympy" group. > > To post to this group, send email to [email protected]. > > To unsubscribe from this group, send email to > [email protected]. > > For more options, visit this group at > http://groups.google.com/group/sympy?hl=en. > > > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/sympy?hl=en. > > -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
