On Thu, Jun 7, 2012 at 6:37 PM, [email protected] <[email protected]> wrote: > In [22]: f(y).atoms(f(x)) > Out[22]: set([f(y)])
I would say no since f(x) != f(y); I would expect f(y).atoms(f) to return f(y), however (and it does). -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
