Here is one other integral sympy cannot do, but which shouls not be to
difficult, it should be possible to do it symbolically,
the last integral in the following output:
In [1]: t1,t2,t3 = symbols('t1 t2 t3', real=True)
In [2]: beta=symbols('beta', real=True)
In [3]: integrate( (t1*t2*t3)**beta * (t1-t2)*(t1-t3)*(t2-t3),
(t1,0,1),(t2,0,1),(t3,0,1))
Out[3]: 0
In [4]: integrate( (t1*t2*t3)**beta * abs((t1-t2)*(t1-t3)*(t2-t3)),
(t1,0,1),(t2,0,1),(t3,0,1))
Out[4]:
1 1 1
⌠ ⌠ ⌠
⎮ ⎮ ⎮ β
⎮ ⎮ ⎮ (t₁⋅t₂⋅t₃) ⋅│(t₁ - t₂)⋅(t₁ - t₃)⋅(t₂ - t₃)│ d(t₁) d(t₂) d(t₃)
⌡ ⌡ ⌡
0 0 0
Kjetil
--
"If you want a picture of the future - imagine a boot stamping on the
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George Orwell (1984)
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