On Thu, Aug 30, 2012 at 9:25 AM, Chris Smith <[email protected]> wrote:
> On Thu, Aug 30, 2012 at 5:19 PM, David Joyner <[email protected]> wrote:
>> I guess the bottom line is I'm wondering how to enter the generators
>> of the Rubik's cube group, eg at
>
>>>> from sympy.combinatorics.generators import rubik_cube_generators
>>>> gens = rubik_cube_generators()
>
> A single one might be entered in cycle notation as:
>
> Permutation([(0, 2, 7, 5), (1, 4, 6, 3), (8, 32, 24, 16), (9, 33, 25,
> 17), (10, 34, 26, 18)])
When I enter that I get an error:
>>> Permutation([(0, 2, 7, 5), (1, 4, 6, 3), (8, 32, 24, 16), (9, 33, 25,17),
>>> (10, 34, 26, 18)])
Traceback (most recent call last):
File "<console>", line 1, in <module>
File
"/Users/davidjoyner/pythonfiles/sympy/sympy/combinatorics/permutations.py",
line 455, in __new__
(len(temp) - 1))
ValueError: Integers 0 through 19 must be present or (for cyclic
notation) size must be given.
>
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