In the special case where, in the expression (x+y)**n , n is non-integer Rational, shouldn't the expansion come out to be a series of the form
y**n+n*x*y**n-1+0.5*n*(n-1)*(x**2)*(y**n-2)+...+O(x**6) ? Maybe this shouldn't be the default return for expand, but it would be nice to have the option of getting that particular binomial series, especially if value of n is known. Something like (x+y+z)**n could be written by substituting (y+z) for y in the above expansion (Thats how WolframAlpha shows it) or we could use recursion to expand each term of the form (y+z)**(n-r) -- You received this message because you are subscribed to the Google Groups "sympy" group. To view this discussion on the web visit https://groups.google.com/d/msg/sympy/-/biXXPIO16IAJ. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
