Thanks for the ideas. I will probably go for the second one at least for now.

On 1 November 2012 19:45, Matthew Rocklin <[email protected]> wrote:
> If you're willing to keep your index knowledge around separately you can
> build a matrix expression and then subs in immutableMatrices
>
> X, Y = MatrixSymbol('X', 2, 2), MatrixSymbol('Y', 2, 2)
> idx = (0, 1)
>
> expr = (X+Y)*Y
>
> nx, ny = ImmutableMatrix(...), ImmutableMatrix(...)
>
> expr.subs({X: nx, Y: ny})[idx[0], idx[1]]
>
>
> On Thu, Nov 1, 2012 at 1:42 PM, Matthew Rocklin <[email protected]> wrote:
>>
>> Short answer, you can't yet. Current issues are as follows
>>
>> MatrixExprs doesn't yet support fancy indexing so you'll have to be
>> explicit and use p[i, j] and not p[i] --- this could be fixed by improving
>> the `__getitem__` method in MatrixExpr
>>
>> p[i, j] yields a Symbol with the name "%s_ij"%p.name . This object has no
>> connection back to the original p. --- this could be fixed by creating some
>> sort of Element(Symbol) class.
>>
>>
>> On Thu, Nov 1, 2012 at 1:36 PM, Stefan Krastanov
>> <[email protected]> wrote:
>>>
>>> This is unrelated to the previous question about matrix expressions.
>>>
>>> How can I do the following
>>>
>>>
>>> >>> p = MatrixSymbol('p', 2, 1)
>>> >>> p[0].subs(p, Matrix([5, 6]))
>>> 5
>>> >>> p[x].subs(p, Matrix([5, 6])).subs(x, 0)
>>> 5
>>>
>>> The first one is more important for me than the second one.
>>>
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>>
>
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