I am unsure how this approach will inter-operate with the rest of SymPy. For this object to be useful it must be able to work with the rest of sympy's functions. For instance will this work with your idea:
solve(x+pm(y), x) ---> -pm(y) There are many more questions, and I am a bit unsure whether this will be useful (just my opinion), however they can wait. For now we can focus on: 1. Is it useful? 2. Will it work seamlessly with the rest of sympy? On 7 November 2012 19:38, Sachin Joglekar <[email protected]> wrote: > @asmeurer, > I would like to start working on this, if no one else already has. We could > create a class 'pm' which would return, as you suggested x for pm[0] and -x > for pm[1]. We could go further and overload the different binary operators > like +,-,* etc for pm such that- > x + y**2*(z+pm(c)) gives > [x+y**2*(z+c), x+y**2*(z-c)] > This list could then be used to access both the values. Moreover, two > expressions with a single difference of plus or minus could be combined by > recursively breaking down the expression and its sub-expressions to their > args until we get the difference in sign. This would take some efforts, but > can be done. (if this is not true, to_pm would return False) > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/sympy/-/vLmyWg0SUW8J. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/sympy?hl=en. -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
