An expression like this returns like so: (2 * sin(3 * x) + 3).find(sympy.Function) >>> sin(3 * x)
how do I get the output >>> sympy.sin instead? i.e. find just the function being used? I don't want to do (2 * sin(3 * x) + 3).has(sympy.sin) for each possible function, unless I have to. -- You received this message because you are subscribed to the Google Groups "sympy" group. To view this discussion on the web visit https://groups.google.com/d/msg/sympy/-/KMb2s65U7CMJ. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
