On 28.01.2013 10:21, Alexey U. Gudchenko wrote: > M Dx = Dx M
Will correct that, under this formula, I could see construction of a differential operator and not the applying of differential operators to the constant matrix (which obviously result in zero). That is I meant that [ a 0 ] [ (a Dx) 0 ] [ ] Dx = [ ] [ 0 a ] [ 0 (a Dx)] And then > (M Dx) A(x) = Dx (M A(x)) -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sympy?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
