> But if all it is is converting a Derivative into some expression, > couldn't the whole thing be done with a single call to .replace()? I > suppose things get a little more tricky than that for higher order > derivatives, but not by much.
I think that the original idea was to *generate* the expression, often called the "difference stencil", automatically. Something like >>> make_stencil(D(f(x), x), order=2) (f[i+1] -2 * f[i] + f[i-1]) / (2*h) but for arbitrary order and also multivariate D. This is just something that's very error prone when done by hand. -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sympy?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
