Can you give a concrete example of what you would like the output to be? Do you want a single solution for symbolic n, or just a function that takes a specific number n as input and gives an output?
Also, what are your base cases? Aaron Meurer On Sat, Mar 2, 2013 at 6:54 PM, <[email protected]> wrote: > Hi, > I have a system of recurrent relationships, like the following (simplified > example): > > a = Function('a') > b = Function('b') > k = Symbol('k', integer=True) > > a(k+1) == b(k+1,k)*a(k) + 2*b(k+1,k) > b(k+2,k) == b(k+2,k+1)*b(k+1,k) > > Is it possible to give these to SymPy and have it automatically figure out > what (a(k+n) - a(k)) would look like for some arbitrary integer n? I > don't know what this operation is called in SymPy terms, so no idea where to > start... > > Thanks! > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at http://groups.google.com/group/sympy?hl=en. > For more options, visit https://groups.google.com/groups/opt_out. > > -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sympy?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
