On Wednesday, April 3, 2013 1:51:49 AM UTC+5:30, Manoj Kumar wrote:
>
> I had been reading this paper by Dr.Starrett and I can very well recall 
> somewhere in my freshman year about PDE's of this type.
>
> Fx * a(x, y) + Fy* b(x, y) = c(x, y)
>
> that can be solved by this method
>
> dx                       dy                 ds
> ----          ===    ---------   ===   --------
> a(x, y)                b(x, y)            c(x, y)
>
> where s can be found by just integrating   (dx * c(x, y)) / a(x, y)
>
> Hi Manoj, you might want to check this method, because if you directly 
substitute Fx = df/dx = c(x,y)/a(x,y) and Fy = df/dy = c(x,y)/b(x,y), you 
get LHS = 2*c(x,y). You can take a look at 
http://geo.hmg.inpg.fr/loret/enseee/maths/enseee-maths-IBVPs-3.pdf , which 
discusses the solution of the pdes of this type based on their 
classification.
 

> However, looking at this random example.
>
> Fx( x* y) + Fy( x**2 * y) = 1
>
> This should be solved by:
>
> dx              dy                        df
> -----   ===   --------          ===  --------
> (x*y)           (x**2 * y)             1
>
>
> just taking the first and the third part,    dx / (x * y) = df , we get f 
> = ln(x) / y
>
> However If I substitute it back in the equation,  fx = 1 / (x*y)  and fy = 
> -ln(x) / (y**2) , it doesn't seem to add up to one. Am I missing something, 
> really basic over here?
>

Regards,
Ankit Agrawal,
Senior undergrad in EE,
IIT Bombay. 

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