Looks like we will run into more and more trouble representing the solutions.
The latest is that when solving quadratic Diophantine equation, A*x**2 + B*x*y + C*y**2 + D*x + E*y + F = 0, for the case B**2 - 4AC > 0, when we know a basic solution, all the other solutions can be represented as a recurrence relation. Suppose, we find that X0 = 9 and Y0 = 4 is a solution to the given equation, we can find P, Q, K, R, S, L such that, Xn+1 = PXn + QYn + K and Yn+1 = RXn + SYn + L where Xn+1 and Yn+1 will also be solutions to the equation given that Xn and Yn are solutions. How do we represent this in the solution? Perhaps as a matrix? Regards, Thilina -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sympy. For more options, visit https://groups.google.com/groups/opt_out.
