On Sun, Jul 7, 2013 at 5:02 AM, Stefan Krastanov
<[email protected]> wrote:
> A small correction: It is not a matplotlib object. However, if you use
> the matplotlib backend
> you can access the encapsulated matplotlib objects through `p._backend`.

Indeed, thanks guys.


>
> On 6 July 2013 20:43, Aaron Meurer <[email protected]> wrote:
>> Yes, our documentation for plot() could be better (pull requests welcome!).
>> Basically, plot(show=False) just returns the matplotlib object, and so you
>> can call all the normal matplotlib functions on it.
>>
>> Aaron Meurer
>>
>>
>> On Sat, Jul 6, 2013 at 12:31 PM, Amit Saha <[email protected]> wrote:
>>>
>>> This is something which was not obvious to me (or I don't read well),
>>> so posting it in case it helps someone:
>>>
>>> >>> from sympy import plot
>>> >>> from sympy import Symbol
>>>
>>> >>> x=Symbol('x')
>>> >>> p = plot(2*x+3,show=False)
>>>
>>> Now, you have a object of the Plot class returned in p.
>>>
>>> So, you can either see the graph now:
>>> >>> p.show()
>>>
>>> Or save it:
>>>
>>> >>> p.save('/tmp/foo1.png')
>>>
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>>
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