This is what I was looking for... thanks again for the help! On Tuesday, July 9, 2013 9:10:28 AM UTC-5, wade conklin wrote: > > I'm new to python, so I apologize if this is covered somewhere else or if > my post is not formatted correctly. > > I have a differential equation which I want to parameterize in polar > coordinates > > diff(y, x, 2) / ((1 + diff(y, x) ^ 2) ^ 3/2) > > where x = r * cos(theta) and y = r * cos(theta) > > how do I solve something like this? > > Thanks! >
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