I have two questions.
a*x == b*y == c*z
What is the shortest way to enter this? I have only figured out the
solution below, to use Eq twice.
Eq(a*x, b*y), Eq(a*x, c*z)
The other question may be difficult to explain. Let me show an example.
>>> var('w0 w1 w2 x0 x1 x2 y0 y1 y2 z0 z1 z2 k')
>>> solve([Eq(w0*w1+x0*x1, k), Eq(w0*w2, x0*x2)], [w0, x0])
>>> solve([Eq(w0*w1+x0*x1+y0*y1, k), Eq(w0*w2, x0*x2), Eq(w0*w2, y0*y2)],
[w0, x0, y0])
>>> solve([Eq(w0*w1+x0*x1+y0*y1+z0*z1, k), Eq(w0*w2, x0*x2), Eq(w0*w2,
y0*y2), Eq(w0*w2, z0*z2)], [w0, x0, y0, z0])
When you run this, you'll notice that the result follows a certain pattern.
Is it possible to get a universal function out of this, that applies for n
different n0/n1/n2 variables, so you don't need to run solve again when you
add another variable? I don't even know if this is mathematically possible.
Thanks.
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