If you define you functions like this:
theta = Function('theta')(t)
Your second bit of code will work.
Jason
moorepants.info
+01 530-601-9791
On Wed, Oct 16, 2013 at 12:46 PM, Aaron Meurer <[email protected]> wrote:
> Yes, functions need to be applied to some argument to make sense.
> Otherwise, it would be like writing exp(sin) or sin**2 instead of
> exp(sin(x)) and sin(x)**2.
>
> Technically speaking, f is a class, while f(t) is an object, and SymPy
> expressions must consist of SymPy objects, not classes.
>
> Aaron Meurer
>
> On Wed, Oct 16, 2013 at 9:58 AM, Cavendish McKay
> <[email protected]> wrote:
> > Having worked through this a bit more, I've found the bit of syntax that
> > makes the difference between working and not working, but I'm not sure I
> > fully understand it. If I do
> >
> > m,g,r,b,t = symbols("m,g,r,b,t")
> > theta = Function('theta')
> > x = (r+b)*sin(theta(t)) + r*theta(t)*cos(theta(t))
> >
> > I don't have problems, but if I do
> >
> > m,g,r,b,t = symbols("m,g,r,b,t")
> > theta = Function('theta')
> > x = (r+b)*sin(theta) + r*theta*cos(theta)
> >
> > I get the TypeError from my previous email. What exactly is the
> difference
> > between theta and theta(t) when I have declared theta=Function('theta')?
> >
> > Cavendish
> >
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