Hi,
I understand that series() supports unevaluated Taylor series setting
n=None.
I am writing a Wester test case X3 that probably needs unevaluated Taylor
series; series(sin(x))/series(cos(x))==series(tan(x)) . In Mathematica
syntax:
In[10]:= (* Note: sin(x) = x - x^3/6 + x^5/120 - x^7/5040 + O(x^9)
cos(x) = 1 - x^2/2 + x^4/24 - x^6/720 + O(x^8)
tan(x) = x + x^3/3 + 2/15 x^5 + 17/315 x^7 + O(x^9) *)
0. Second
In[11]:= tsin = Series[Sin[x], {x, 0, 7}]
0. Second
3 5 7
x x x 8
Out[11]= x - -- + --- - ---- + O[x]
6 120 5040
In[12]:= tcos = Series[Cos[x], {x, 0, 7}]
0. Second
2 4 6
x x x 8
Out[12]= 1 - -- + -- - --- + O[x]
2 24 720
In[13]:= (* Note that additional terms will be computed as needed *)
0. Second
In[14]:= tsin/tcos
0.01 Second
3 5 7
x 2 x 17 x 8
Out[14]= x + -- + ---- + ----- + O[x]
3 15 315
In[15]:= Series[Tan[x], {x, 0, 7}]
0.01 Second
3 5 7
x 2 x 17 x 8
Out[15]= x + -- + ---- + ----- + O[x]
3 15 315
if I try with Sympy series(sin(x), n=None)/series(cos(x), n=None)) I
get TypeError: unsupported operand type(s) for /: 'generator' and
'generator'.
Is i use series(sin(x))/series(cos(x)) it returns (x - x**3/6 + x**5/120 +
O(x**6))/(1 - x**2/2 + x**4/24 + O(x**6))
Is the unevaluated Talyor series support incomplete or is there any other
way SymPy can implement this test case?
Thanks,
Pablo Puente
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