Le mardi 5 novembre 2013 10:52:00 UTC+1, Pierre H a écrit :
>
>
> >>> Function('f')(x).__class__
> f
>
>
I just dig a bit further and got in the idea that there are metaclass
involved when "evaluating" a function.
I guess my question is just a consequence of my ignorance of the topic of
metaclasses. (I was imagining a more "flat" structure for function
objects). Sorry for the noise.
best,
Pierre
--
You received this message because you are subscribed to the Google Groups
"sympy" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/sympy.
For more options, visit https://groups.google.com/groups/opt_out.
