Yes, it should, but it's a rabbit hole. Much better would be to just
fix https://code.google.com/p/sympy/issues/detail?id=1497 already.

Aaron Meurer

On Wed, Nov 20, 2013 at 10:42 PM,  <[email protected]> wrote:
> The culprit here is fraction() from the simplify module, which expands the
> Mul() expression, ignoring the evaluate=False parameter. There is a simple
> fix, which is to use the original expression rather than the (modified)
> numerator. One could ask whether fraction() should respect the
> evaluate=False parameter or not. It is part of the "simplify" module after
> all. Then again, it is quite possible to apply fraction to unevaluated Mul
> object in a way that maintains the unevaluated property.
>
> https://github.com/sympy/sympy/pull/2617
>
>
> On Tuesday, November 19, 2013 10:26:59 PM UTC-5, Aaron Meurer wrote:
>>
>> Yes, unfortunately, unevaluated expressions tend to be "unstable".
>> Sometimes things will do what would normally be an innocuous
>> transformation that ends up evaluating it. These bugs have been mostly
>> fixed for the pretty printer, but I guess they are still there for the
>> latex printer.
>>
>> Aaron Meurer
>>
>> On Mon, Nov 18, 2013 at 4:30 AM,  <[email protected]> wrote:
>> > Hi,
>> >
>> > I work with unevaluated Adds and Muls and today found this:
>> >
>> >>>> from sympy import latex, Mul, Symbol
>> >>>> x = Symbol('x')
>> >>>> e = Mul(-2, x + 1, evaluate=False)
>> >>>> print e
>> > -2*(x + 1)
>> >>>> print latex(e)
>> > - 2 x + 2
>> >
>> > The first print is correct but the second one is not. It's not about
>> > simply
>> > dropping parentheses when they are needed. In that case the second print
>> > would read - 2 x + 1 so some computation took place.
>> >
>> > Regards
>> > --
>> > Greg
>> >
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