Well, I've used that:
arg = something
solutions = solve(sin(arg))
solutions_trig = [(sol - pi) for sol in solutions]
as I remember, sin is fine with it because at [-1, 1] it's mirroring itself
at (0, 0) for most functions.
среда, 27 ноября 2013 г., 0:43:03 UTC+4 пользователь Aaron Meurer написал:
>
> It doesn't support it directly, mainly because there is no nice way
> for solve to return parameterized solutions, but you can do it
> yourself pretty easily. Just note that sin is 2*pi periodic, so do
>
> solve(sin(x + 2*n*pi), x)
>
> where n = Symbol('x', integer=True). Then substitute various integer
> values of n in the solutions to get all the answers. If there are
> multiple trig functions in your expression, to get the full set of
> solutions in general, you'll need to use a different parameter for
> each function.
>
> Aaron Meurer
>
>
> On Tue, Nov 26, 2013 at 12:28 PM, Alexander Birukov
> <[email protected]<javascript:>>
> wrote:
> > Hello everyone.
> >
> > Basic example:
> > solve(sin(x)) = [0, pi]
> >
> > I would like to have:
> > solve(sin(x)) = [-pi, 0, pi]
> >
> >
> > Can lib handle it or I should do it myself?
> >
> >
> > Thanks, Alexander.
> >
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