However gruntz gives the correct result:-
gruntz((x*exp(x)) / (exp(x)-1), x, -oo) gives 0
The part of code that is going wrong is already labeled as XXX: todo
More specifically the following:-
if abs(z0) is S.Infinity:
# XXX todo: this should probably be stated in the
# negative -- i.e. to exclude expressions that should
# not be handled this way but I'm not sure what that
# condition is; when ok is True it means that the leading
# term approach is going to succeed (hopefully)
It should exclude some expressions and I guess this is one of them.
I'll try to understand and fix it.
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