On Tue, Mar 4, 2014 at 4:08 AM, Anurag Hota <[email protected]> wrote: > Issue in #2978
Here is the link: https://github.com/sympy/sympy/pull/2978 > > Ondrej, > I made it both time dependent/independent perturbation. > The issue is for 2nd order correction in time independent perturbation, > it show the term infinity whereas i want a summation. How do i add that? > > ∞(<n|kx|n>)2+(<0|kx|n>)2E(n)−E(0) How is the infinity generated? I don't quite understand your code and it can't be imported, so that I can play with it. Let's discuss this on the PR: https://github.com/sympy/sympy/pull/2978#issuecomment-36658825 Ondrej > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at http://groups.google.com/group/sympy. > To view this discussion on the web visit > https://groups.google.com/d/msgid/sympy/060c5b02-8f91-498c-8e97-1580a83fedf5%40googlegroups.com. > For more options, visit https://groups.google.com/groups/opt_out. -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sympy. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/CADDwiVCEoY1bGBntXw6gqi-gg33WXXFTUFZphfb%3D3T8-R_wAQA%40mail.gmail.com. For more options, visit https://groups.google.com/groups/opt_out.
