I think it's a corner case in terms of how the result is given precision.
It's off by 1 in this case. And being off by one doesn't affect the boolean:
```
>>> Float('.1',0)==.1
True
>>> Float('.1',1)==.1
True
```
On Tuesday, September 2, 2014 8:03:18 PM UTC-5, Aaron Meurer wrote:
>
> I think it's a bug with the printer. S(0.06).round(1) == 0.1 gives
> True. Can you open an issue for it?
>
> Aaron Meurer
>
> On Tue, Sep 2, 2014 at 7:28 AM, Duane Nykamp <[email protected]
> <javascript:>> wrote:
> > Is this the intended result of rounding to one decimal place? Sympy
> needs
> > to go back to school on rounding. :)
> >
> > In [13]: S(0.06).round(1)
> > Out[13]: 0.e-1
> >
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