Have a look at parse_expr() in sympy.parsing.sympy_parser.

Aaron Meurer

On Wed, Oct 8, 2014 at 8:42 AM, Mateusz Paprocki <[email protected]> wrote:
> Hi,
>
> On 8 October 2014 12:05,  <[email protected]> wrote:
>> Is there any function in SymPy can take this TEX command as an input
>>
>> (-6x^2-x-7)(2x^3+3x^2-2x-5)
>>
>> to find the derivative?
>
> I wanted to suggest a mathematica parser for this:
>
> In [1]: import sympy.parsing.mathematica as m
>
> In [2]: m.parse("(-6x^2-x-7)(2x^3+3x^2-2x-5)")
> Out[2]: '(-6*x**2-x-7)*(2*x**3+3*x**2-2*x-5)'
>
> In [3]: eval(_)
> Out[3]:
> ⎛     2        ⎞ ⎛   3      2          ⎞
> ⎝- 6⋅x  - x - 7⎠⋅⎝2⋅x  + 3⋅x  - 2⋅x - 5⎠
>
> But there is bug there and the above output requires the following patch:
>
> diff --git a/sympy/parsing/mathematica.py b/sympy/parsing/mathematica.py
> index f86d59a..eeb12f7 100644
> --- a/sympy/parsing/mathematica.py
> +++ b/sympy/parsing/mathematica.py
> @@ -39,7 +39,7 @@ def parse(s):
>          (r"\A\((.+)\)([\w\.].*)\Z",  # Implied multiplication - (a)b
>          lambda m: "(" + parse(m.group(1)) + ")*" + parse(m.group(2))),
>
> -        (r"\A([\d\.]+)([a-zA-Z].*)\Z",  # Implied multiplicatin - 2a
> +        (r"\A([+-]?[\d\.]+)([a-zA-Z].*)\Z",  # Implied multiplicatin - 2a
>          lambda m: parse(m.group(1)) + "*" + parse(m.group(2))),
>
>          (r"\A([^=]+)([\^\-\*/\+=]=?)(.+)\Z",  # Infix operator
>
> Mateusz
>
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