I don't think integrate() tries any simplification. Ideally it
shouldn't have to.

Aaron Meurer

On Sun, Oct 12, 2014 at 6:12 AM, Francesco Bonazzi
<[email protected]> wrote:
>
>
> On Sunday, October 12, 2014 1:50:10 AM UTC+2, Aaron Meurer wrote:
>>
>> That's correct. If integrate() returns an unevaluated Integral, it
>> means the algorithm couldn't compute an integral. The fu() function is
>> able to simplify this expression (it equals 2*sin(x)), so
>> integrate(fu(fx), x) works.
>>
>
> Why is fu( ) not attempted in the integrate( ) algorithm?
>
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