If you suspect that you are working with something that is pretty
symmetric, something like this can work:
>>> def group_factor(r, *p):
... a = []
... for g in p:
... i,r = r.as_independent(*g)
... a.append(factor(i))
... return Add(*a)
...
>>> n,d = [i.expand() for i in E.expand().as_numer_denom()]
>>> pairs = (x1,x2),(y1,y2),(r1,r2)
>>> pprint(group_factor(n,*pairs)/group_factor(d,*pairs))
2 / 2 2 2 2\
(x1 - x2) *(y1 + y2) + (y1 - y2)*\- r1 + r2 + y1 - y2 /
----------------------------------------------------------
2 2
2*(x1 - x2) + 2*(y1 - y2)
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