You can get approximate solutions using nsolve, e.g.
>>> nsolve(2*x*cos(2*x) + sin(2*x),1)
mpf('1.0143789190552171')
On Tuesday, January 13, 2015 at 4:42:24 PM UTC-6, Amit Saha wrote:
>
> On Wed, Jan 14, 2015 at 8:27 AM, Aaron Meurer <[email protected]
> <javascript:>> wrote:
> > I don't think there are analytic solutions. The equation is equivalent
> to
> > solving tan(x) = -x.
> >
> > Aaron Meurer
> >
> > On Tue, Jan 13, 2015 at 4:24 PM, Sergey Kirpichev <[email protected]
> <javascript:>>
> > wrote:
> >>
> >> On Wednesday, January 14, 2015 at 1:14:01 AM UTC+3, Amit Saha wrote:
> >>>
> >>> Thanks for any insights into this and whether there is a workaround.
> >>
> >>
> >> What do you expect instead and why? Not all algebraic equations
> >> have analytic solutions. Mathematica can't do this eq as well.
>
> Thanks for the quick replies all. The Traceback made me wrongly
> believe that perhaps sympy is doing something wrong. To be fair to
> myself, I was also laid astray by:
>
> http://www.wolframalpha.com/input/?i=solve%282*x*cos%282*x%29+%2B+sin%282*x%29%29
>
>
> Which gave me an approximate solution - I should have checked myself.
>
> Anyway, thanks all and sorry for the noise.
>
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