On Wed, Jan 14, 2015 at 12:02 AM, Chris Smith <[email protected]> wrote:

> By allowing the (-1)**(1/3) to remain we leave open (as with Rational
> bases) the option of getting to the real root with real_root. I wish we had
> a good mechanism to check if something like root(x, 3) + 2 == 0 when
> substituting in -8 for x. It is for this reason that the following returns
> no solution:
>
> >>> solve(root(x,3)+2)
> []
>

I suppose this is right. There is no x that when plugged in to that
equation, gives 0. Maybe 8*exp_polar(3*pi*I) could be considered a
solution.

Aaron Meurer


>
> On Tuesday, January 13, 2015 at 3:20:46 PM UTC-6, Aaron Meurer wrote:
>>
>> Without commenting on your proposal, I'd like to point out that point of
>> the principal nths root is that all other nth roots are the powers of that
>> root.
>>
>> Aaron Meurer
>>
>> On Tue, Jan 13, 2015 at 3:14 PM, Chris Smith <[email protected]> wrote:
>>
>>> In PR 8814 <https://github.com/sympy/sympy/pull/8814> I write,
>>>
>>>
>>> Something has to be done to allow one to compute real_root(float, odd)
>>> as real. At first I thought to handle this in real_root, but then I thought
>>> it might be better to catch it in _eval_power itself. Which do you think is
>>> better:
>>>
>>> # This is how a negative rational base behaves:
>>> >>> root(S('-1/10'),3)
>>> (-1)**(1/3)*10**(2/3)/10
>>> # Now, for a negative float...
>>> >>> root(S('-.1'),3)0.464158883361278*(-1)**(1/3)  # <-- should a negative 
>>> >>> float give this (a)>>> _.n()0.232079441680639 + 0.401973384383085*I  # 
>>> >>> <-- or this (b)?
>>>
>>> The SymPy  trend is to fully evaluate an expression if args are numbers,
>>> but by selecting the principle root in the case of Pow, the user looses the
>>> option to select the real branch post-calc. (Hence, I favor not fully
>>> evaluating in this case, selecting behavior (a).) If the power is not an
>>> odd rational, the usual, fully evaluated result is obtained.
>>>
>>>
>>> /c
>>>
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