Thanks Aaron, I'm going to use .name. Perhaps an auto_inject transformation
will be useful for parse_expr. BTW, why is var() not recommended?
I cannot think of any way to avoid using var() when parsing string
expressions.

It's recommended not to use :func:`var` in library code, where
:func:`symbols` has to be used

On Wed, Jan 28, 2015 at 4:31 PM, Aaron Meurer <[email protected]> wrote:

> auto_symbol doesn't do namespace injection. It just means that the parser
> won't fail with a NameError (undefined names in the namespace that the
> parser users will be converted to Symbols). Your hack works (I would use
> each_sym.name instead of __str__(), and note that str(each_sym) is the
> same as each_sym.__str__()).
>
> Aaron Meurer
>
> On Wed, Jan 28, 2015 at 4:28 PM, Denis Akhiyarov <
> [email protected]> wrote:
>
>> Can I use parse_expr to parse an expression such as
>> "a1*x1**2+a2*x1+a3+a4*x1*x2+a5*x2**2" and inject the symbols into globals
>> or locals namespace?
>>
>> Looks like auto_symbol is not doing this. So I have to manually inject
>> each symbol using sympy.var() method.
>>
>>
>> exp0=parse_expr("a1*x1**2+a2*x1+a3+a4*x1*x2+a5*x2**2",transformations=(auto_number,auto_symbol))
>> exp0.subs(a1,10)
>>
>>
>> ---------------------------------------------------------------------------NameError
>>                                  Traceback (most recent call 
>> last)<ipython-input-4-19dc46bbe490> in <module>()----> 1 exp0.subs(a1,10)
>> NameError: name 'a1' is not defined
>>
>>
>>
>> But after my hack:
>>
>> for each_sym in exp0.atoms(sympy.Symbol):
>>     sympy.var(each_sym.__str__())
>>
>>
>> exp0.subs(a1,10)
>>
>> 2*x1 + a3 + a4*x1*x2 + a5*x2**2 + 10*x1**2
>>
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