On Fri, Feb 13, 2015 at 3:42 PM, Ian Bell <[email protected]> wrote:

> I am trying to do an integration like this:
>

Was there supposed to be something here? It's just showing up as empty
space for me.

Aaron Meurer


>
>
>
> Ultimately the result I should be able to get is -log(1-z)
>
> Manual integration shows that you can integrate(1/(1-z),z) -> -log(z-1),
> evaluation at the limits yields -log(z-1) - (-log(-1)) which you can
> simplify to -log(1-z).  How can I tell sympy to delay evaluation until
> after it has done the simplification?  I guess that it first does log(-1),
> which it isn't happy about...
>
> Ian
>
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